5b^2-33b-56=0

Solution for 5b^2-33b-56=0 equation:

5b^2-33b-56=0

a = 5; b = -33; c = -56;
Δ = b2-4ac
Δ = -332-4·5·(-56)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-47}{2*5}=\frac{-14}{10}
=-1+2/5
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+47}{2*5}=\frac{80}{10}
=8
$